Answer to Question #293863 in Physics for joyjoy

Question

A 0.750-cm diameter shell contains a uniformly distributed charge of 65.4 pC on its surface. Determine

the potential near the surface of the sphere.

Answer 1

Given:

$d=0.750\;\rm cm$

$q=65.4*10^{-12}\;\rm C$

The potential near the surface of the sphere is given by

$$V=k\frac{q}{R}$$

$$V=9*10^9\frac{65.4*10^{-12}}{0.750/2*10^{-2}}=157\:\rm V$$