Answer to Question #293030 in Physics for Fidel

Question

Given the altitude and the zenith distance of a star as 50 degree 25minutes and 39 degree 35minutes respectfully calculate for the declination and latitude of the star

Answer 1

With declination δ and latitude Φ=41.71°, for the altitude h of the star, we have:

$$h=90°-Φ+δ,\\ 50°25'=90°-40.71°-\delta,\\\space\\ \delta=1°8'.$$