Question

A brass rod is 2m long at a certain temperature. What is the length for a temperature rise of 100k.(take x=0.000018-1)

Answer 1

Given:

$l_0=2\:\rm m$

$\Delta T=100\:\rm K$

$\alpha=0.000018\:\rm K^{-1}$

The thermal linear expansion equation says

$$l=l_0(1+\alpha\Delta T)\\ =\rm 2\: m(1+0.000018\: K^{-1}*100\: K)=2.0036\: m$$