Answer to Question #292956 in Physics for Ierm_ak

Question #292956

A brass rod is 2m long at a certain temperature. What is the length for a temperature rise of 100k.(take x=0.000018-1)


1
Expert's answer
2022-02-01T15:33:51-0500

Given:

l0=2ml_0=2\:\rm m

ΔT=100K\Delta T=100\:\rm K

α=0.000018K1\alpha=0.000018\:\rm K^{-1}


The thermal linear expansion equation says

l=l0(1+αΔT)=2m(1+0.000018K1100K)=2.0036ml=l_0(1+\alpha\Delta T)\\ =\rm 2\: m(1+0.000018\: K^{-1}*100\: K)=2.0036\: m


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