Question #292853

A 9 microcoulomb test charge moves along +x-axis at a speed of 300,000 m/s in the region of 0.75 T magnetic field. Determine the magnetic force on the charge if (a) the field is out of the page; (b) the field is into the page; (c) the field is


downward; (d) the field is upward; (e) the field is 30° above horizontal.




1
Expert's answer
2022-02-02T05:14:08-0500

Assuming +x-axis is in the plane of the page:

(a) F=qvBsin90°=2 N.F=qvB\sin90°=2\text{ N}.

(b) F=qvBsin90°=2 N.F=qvB\sin90°=2\text{ N}.

(c) F=qvBsin90°=2 N.F=qvB\sin90°=2\text{ N}.

(d) F=qvBsin90°=2 N.F=qvB\sin90°=2\text{ N}.

(e) F=qvBsin30°=1 N.F=qvB\sin30°=1\text{ N}.


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