Answer to Question #292532 in Physics for jurin junior

Question

A KTM Commuter train travel between two station, A and B. The train starts from rest from station A and accelerates at a constant rate for 0.5 km until it reaches a speed of 30 m/s. It then travel at this constant speed for T s before decelerating at a constant rate of 1.5 m/s and coming to rest at station B. Determine the value of T if the distance between the two stations 6km. Calculate also the total time taken for the whole journey.

Answer 1

The distance at acceleration: 500m.

The distance at constant speed: 30T.

The distance at deceleration:

$$D=\dfrac{30^2}{2·1.5}=300 \text{ m}.$$

The entire trip is (800+30T) m.