Answer to Question #291622 in Physics for Willz

Question

A machine has an effiency of 75% the work done when the machine is used to raise a load of 50kg through a vertical distance of 6m is

Answer 1

Given:

$\eta=0.75$

$m=50\:\rm kg$

$h=6\:\rm m$

The work done by the machine

$$W=\frac{mgh}{\eta}=\rm\frac{50*9.8*6}{0.75}=3920\:J$$