Question

259L oil of compressibility k=20×10^-6 atm^-1is subjected to a hydraulic press. Find the decrease in the value of the oil when it is subjected to pressure 1.6×10^7

Answer 1

Given:

$V_0=259\:\rm L$

$k=20×10^{-6}\:\rm atm^{-1}$

$\Delta P=1.6\times 10^7\:\rm Pa=157.9\: atm$

The compressibility is given by

$$k=-\frac{1}{V_0}\frac{\Delta V}{\Delta P}$$

The final volume

$$V=V_0+\Delta V=V_0(1-k\Delta P)$$

$$V=\rm 259\: L(1-20*10^{-6}*159.7)=258\: L$$