Answer to Question #291117 in Physics for Bebe

Question

A 0.600 kg mass oscillates at the end of a spring with stiffness of k= 300 N/m. The initial amplitude is 0.500 m. The damping force is proportional to the velocity, "-av".

A. If the amplitude decreases from 0.500 m to 0.350 m in 2.500 s, what is the damping constant "a" ?

Note: The answer in letter A should be 7.44 × 10^-2 kg/s

Answer 1

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