Answer to Question #290376 in Physics for nazarul

Question

A cannonball is fired horizontally at 23.40 m/s from the edge of a 55 m building. Determine the: (a) height of the cannonball from the ground after 2 s. (b) time taken by the cannonball to reach the ground. (c) distance from the base of the building to the point where the its landed.

Answer 1

Given:

$v=\rm 23.40\: m/s$

$H=\rm55\: m$

$g=\rm 9.8\:m/s^2$

(a) height of the cannonball from the ground after 2 s

$$h=H-gt^2/2=55-9.8*2^2/2=35.4\:\rm m$$

(b) time taken by the cannonball to reach the ground

$$t=\sqrt{\frac{2H}{g}}=\sqrt{\frac{2*55}{9.8}}=3.35\: \rm s$$

(c) distance from the base of the building to the point where the its landed

$$L=vt=23.40*3.35=78.4\;\rm m$$