Question #290202

Directions: Solve the following problems stated below. Show your solutions.



a. A -1.49x10^-8 C charge is separated from a -1.15x10^-9 C charge by a distance of 2.01x10^20 m. Determine the repulsive force between the two charges.



b. Two charges (-2.09x10^-18 C and 1.60x10^-19 C) are separated by a distance of 4.01x10^-10 m. Compute the force of attraction between them.

1
Expert's answer
2022-01-24T08:44:40-0500

(a) Given:

q1=1.49108C,q2=1.15109Cq_1=-1.49*10^{-8}{\rm\: C}, \quad q_2=-1.15*10^{-9}\rm\: C

d=2.011020md=2.01*10^{20}\rm\: m


The Coulomb law says

F=kq1q2d2F=k\frac{|q_1||q_2|}{d^2}

F=9.01091.491081.15109(2.011020)2F=9.0*10^9*\frac{1.49*10^{-8}*1.15*10^{-9}}{(2.01*10^{20})^2}

F=3.831048NF=3.83*10^{-48}\:\rm N

(b) Given:

q1=2.091018C,q2=1.601019Cq_1=-2.09*10^{-18}{\rm\: C}, \quad q_2=1.60*10^{-19}\rm\: C

d=4.011010md=4.01*10^{-10}\rm\: m


The Coulomb law says

F=kq1q2d2F=k\frac{|q_1||q_2|}{d^2}

F=9.01092.0910181.601019(4.011010)2F=9.0*10^9*\frac{2.09*10^{-18}*1.60*10^{-19}}{(4.01*10^{-10})^2}

F=1.87108NF=1.87*10^{-8}\:\rm N


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