Question #290147

A superman is sitting on a tree 98m right with a baby he has rescued from the claws of a tiger. Unfortunately the child slips and fall with an initial velocity of 0ms^–². Superman realized what was happening 2 seconds later and flow to catch the child at a speed of 39.2ms^–¹. Calculate



(1) the time superman will fly before catching the child.



(2) the distance superman will fly before catching the child.

1
Expert's answer
2022-01-24T08:45:01-0500

The equation of motion of a superman

ys=39.2(t2)y_s=39.2(t-2)

The equation of motion of a child

yc=9.8t2/2y_c=9.8t^2/2

At the instant when superman catches the child

ys=ycy_s=y_c

39.2(t2)=9.8t2/239.2(t-2)=9.8t^2/2

t28t+16=0t^2-8t+16=0

(1) the time superman will fly before catching the child:

Δt=42=2s\Delta t=4-2=2\:\rm s

(2) the distance superman will fly before catching the child:

ys=39.22=78.4my_s=39.2*2=78.4\:\rm m


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