Question

A stone projected horizontally from the top of a tower with a speed of 5m/s. It lands on the ground level of the horizontal distance of 20m from the top of the tower. Calculate the height of the tower. g= 10m/s²

Answer 1

Given:

$v_0=5\:\rm m/s$

$l=20\:\rm m$

$g=10\:\rm m/s^2$

The height of a tower

$$H=\frac{gt^2}{2}$$

Time of falling

$$t=l/v_0$$

So

$$H=\frac{gl^2}{2v_0^2}=\frac{10*20^2}{2*5^2}=80\:\rm m$$