A stone projected horizontally from the top of a tower with a speed of 5m/s. It lands on the ground level of the horizontal distance of 20m from the top of the tower. Calculate the height of the tower. g= 10m/s²
Given:
"v_0=5\\:\\rm m\/s"
"l=20\\:\\rm m"
"g=10\\:\\rm m\/s^2"
The height of a tower
"H=\\frac{gt^2}{2}"Time of falling
"t=l\/v_0"So
"H=\\frac{gl^2}{2v_0^2}=\\frac{10*20^2}{2*5^2}=80\\:\\rm m"
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