Question #288715

A large chunk of ice with mass of 15.0kg falls from a roof 8.0m above the ground. Assume air resistance is negligible, kinetic energy is 14.25 J. Determine the speed of the ice when it reaches the ground.


Expert's answer

Apply conservation of energy:


12mv2=KEi+mgh, v=2(KEi/m+gh)=2(14.25/15+9.88),v=13.6 m/s.\dfrac12mv^2=KE_i+mgh,\\\space\\ v=\sqrt{2(KE_i/m+gh)}=\sqrt{2(14.25/15+9.8·8)},\\ v=13.6\text{ m/s}.


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