Question #288529

1. Ball thrown at 45° with intial velocity of 25m/s.


Find the


A. Initial velocity


B. Final velocity


C. Acceleration (m/s²)


D. Time ( s )


E. Distance ( m )

1
Expert's answer
2022-01-18T09:36:50-0500

Given:

v0=25m/sv_0=25\:\rm m/s

θ=45\theta=45^\circ


(a)

vix=v0cosθ=25cos45=17.7m/sviy=v0sinθ=25sin45=17.7m/sv_{ix}=v_0\cos\theta=25\cos45^\circ=17.7\:{\rm m/s}\\ v_{iy}=v_0\sin\theta=25\sin45^\circ=17.7\:{\rm m/s}

(b)

vfx=v0cosθ=25cos45=17.7m/svfy=v0sinθ=25sin45=17.7m/sv_{fx}=v_0\cos\theta=25\cos45^\circ=17.7\:{\rm m/s}\\ v_{fy}=-v_0\sin\theta=-25\sin45^\circ=-17.7\:{\rm m/s}

(c)

ax=0m/s2ay=g=9.8m/s2a_{x}=0\:{\rm m/s^2}\\ a_{y}=-g=-9.8\:{\rm m/s^2}

(d)

t=2v0sinθg=225sin459.8=3.6st=\frac{2v_0\sin\theta}{g}=\frac{2*25*\sin45^\circ}{9.8}=3.6\:\rm s

(e)

d=v02sin2θg=252sin909.8=63.8md=\frac{v_0^2\sin2\theta}{g}=\frac{25^2*\sin90^\circ}{9.8}=63.8\:\rm m


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS