A car starting from rest accelerates uniformly and attains a speed of 80m/s in 30s. It maintains this steady speed for another 30s. Then slows down uniformly until it comes to rest in the next 40s. What is the total distance covered?
d1=vt12=80⋅302=1200 m. d2=vt2=80⋅30=2400 m. d3=vt32=80⋅402=1600 m. D=d1+d2+d3=5200 m.d_1=\dfrac {vt_1}2=\dfrac {80·30}2=1200\text{ m}.\\\space\\ d_2=vt_2=80·30=2400\text{ m}.\\\space\\ d_3=\dfrac{vt_3}{2}=\dfrac{80·40}{2}=1600\text{ m}.\\\space\\ D=d_1+d_2+d_3=5200\text{ m}.d1=2vt1=280⋅30=1200 m. d2=vt2=80⋅30=2400 m. d3=2vt3=280⋅40=1600 m. D=d1+d2+d3=5200 m.
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