Answer to Question #288187 in Physics for Nano

Question #288187

Vector a is 6m due north, b is 4 at an angle of 30 degree Celsius above the horizontal what is the resultant vector?


1
Expert's answer
2022-01-18T09:35:13-0500
RN=6+4sin30°=8 m,RE=0+4cos30°=3.46 m,R=RN2+RE2=8.72 m, θ=arctanRNRE=66.6°.R_N=6+4\sin30°=8\text{ m},\\ R_E=0+4\cos30°=3.46\text{ m},\\ R=\sqrt{R_N^2+R_E^2}=8.72\text{ m},\\\space\\ \theta=\arctan\dfrac{R_N}{R_E}=66.6°.


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