1.a. The moment of inertia here is
I=121mL2=0.00853 kg⋅m2.
b. In this case, we will need a parallel axis theorem:
I=121mL2+m(L−x)2=0.0134 kg⋅m2.
2. The angular moments of the clock hands are:
Lh=Ihωh=[310.032⋅0.152][36002π0.15], Ih=6.28⋅10−8 kg⋅m2/s. Lm=Imωm=[310.046⋅0.252][602π0.25]2, Im=2.51⋅10−5 kg⋅m2/s.
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