Question #287734

A nucleus, initially at rest, decays radioactively. In the process, it emits an electron horizontally to the east, with momentum 9.0 X 10–21 kg·m/s and a neutrino horizontally to the south, with momentum 4.8 X 10–21 kg·m/s.

(a) In what direction does the residual nucleus move? (3 marks)

(b) What is the magnitude of its momentum? (3 marks)

(c) If the mass of the residual nucleus is 3.6 X 10–25 kg, what is its recoil velocity? (3 marks)


1
Expert's answer
2022-01-16T13:10:50-0500

(a) Determine the direction:


0=pEr+pEepEr=pEe,0=pSr+pSnpSr=pSn, θr=arctanpSrpEe= =arctan4.810219.01021=28°N of W0=p_{Er}+p_{Ee}→p_{Er}=-p_{Ee},\\ 0=p_{Sr}+p_{Sn}→p_{Sr}=-p_{Sn},\\\space\\ \theta_r=\arctan\dfrac{p_{Sr}}{p_{Ee}}=\\\space\\=\arctan\dfrac{-4.8 · 10^{–21}}{-9.0 · 10^{–21}}=28°\text{N of W}


(b) Determine the magnitude:


pr=pEr2+pNr2= =(4.81021)2+(91021)2=1.021020 kgm/s.p_r=\sqrt{p^2_{Er}+p^2_{Nr}}=\\\space\\ =\sqrt{(-4.8 · 10^{–21})^2+(-9 · 10^{–21})^2}=1.02·10^{-20}\text{ kg}·\text m/\text s.


(c) Determine the velocity:


v=pr/m=28.3 km/s.v=p_r/m=28.3\text{ km/s}.


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