Question

A compound microscope consists of objective and eye piece lens of focal length 0.50cm and 1.00cm respectively. An object is placed 0.55cm from the objective lens and the final image is formed at infinity. Calculate the magnifying power of the glass and the tube L.

Answer 1

Magnification

$M=m_0m_e$

$M=\frac{L}{f_0}\times\frac{D}{f_e}$

Put value

$M=\frac{1.50}{0.50}\times\frac{25}{1}=75$

$M=75$

Tube length

$L=f_0+f_e$

$L=1.00+0.50=1.50cm$