Answer to Question #290477 in Optics for Mark

Question

A spring is stretched 0.75 m by using a force of 30N. What is the constant.?

Answer 1

We know that

x=0.75m

Mg=30N

Now

$Kx=mg$

$K=\frac{mg}{x}$

Put value

$K=\frac{30}{0.75}=40N/m$