Answer to Question #287972 in Optics for Fraol

Question

A particle with in SHM has an equation

X=0.75Sin65t cm. What is:

A. the frequency of the oscillation

B. The amplitude of the oscillation

C. The time period of the oscillation

Answer 1

$x=0.75\sin65t$

$x = A\sin\omega t$

$A = 75 cm\text{ (amplitude)}$

$\omega = 65\text{ (cyclic frequency)}$

$A.f = \frac{\omega}{2\pi}= \frac{65}{2\pi}= 10.35 Hz$

$B. A = 75 cm = 0.75 m$

$C.T = \frac{1}{f}=\frac{1}{10.35}=0.097 s$

$\text{Answer:}$

$A.f = 10.35 Hz$

$B. A = 0.75 m$

$C.T = 0.097 s$