Question

A stamp collector uses a converging lens with focal length 28 cm to view a stamp 16 cm in front of the lens. (a)Where is the image located? (b) What is the magnification?

Answer 1

Solution

Focal length f=28cm.

Distance of object d₀=16cm.

a) using lens formula

$\frac{1}{f}=\frac{1}{d_0}+\frac{1}{d_i}$

Putting all values

Image location

$d_i=\frac{d_0f}{d_0-f}$

Putting all values

$d_i=\frac{16\times28}{16-28}=-37.3cm$

b) magnification power

$=-\frac{d_i}{d_0}\\=-\frac{-37.3}{16}\\=2.33$