The beam of parallel light rays falls onto the surface of water under the angle
60°
. The width of the beam in the air is 10 cm. Find the width of the beam in the water.
n=sinαsinβ, ⟹ β=40.5°,n=\frac{\sin\alpha}{\sin\beta},\implies \beta=40.5°,n=sinβsinα,⟹β=40.5°,
b=acosβcosα=15.2 cm.b=\frac{a\cos\beta}{\cos\alpha}=15.2~cm.b=cosαacosβ=15.2 cm.
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