Determine the total luminous flux emitted by the source if the illumination is
15 lx at the distance 2 m from that source. The luminous intensity is equal in all directions.
source if the illumination=15 lx
r=2 m
I=EAI=\frac{E}{A}I=AE
Intensity
I=154πr2I=\frac{15}{4\pi r^2}I=4πr215
Put value
I=154×3.14×4=0.2985lx/m2I=\frac{15}{4\times3.14\times4}=0.2985lx/m^2I=4×3.14×415=0.2985lx/m2
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