Solution;
Work done in process AB;
WAB=−PAVAln(VAVB)
WAB=−5×1.031×105×10×10−3×ln(1050)
WAB=−8151.80J
Work done in process BC;
WBC=−PB(VA−VB)
WBC=−1×1.031×105(10−50)×10−3
WBC=4124J
Work done in process CA;
WCA=0
Therefore,the net work done is;
Wnet=QAB+QBC+QCA
Wnet=8151.80+4124+0
Wnet=12275.8J
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