Answer to Question #309942 in Molecular Physics | Thermodynamics for Zizu

Question #309942

one mole of an ideal monoatomic gas is taken through the cycle shown in the figure. the process A:B is a reversible isothermal expansion. calculate the net work done by the gas?

1
Expert's answer
2022-03-13T18:48:26-0400

Solution;

Work done in process AB;

WAB=PAVAln(VBVA)W_{AB}=-P_AV_Aln(\frac{V_B}{V_A})

WAB=5×1.031×105×10×103×ln(5010)W_{AB}=-5×1.031×10^5×10×10^{-3}×ln(\frac{50}{10})

WAB=8151.80JW_{AB}=-8151.80J

Work done in process BC;

WBC=PB(VAVB)W_{BC}=-P_B(V_A-V_B)

WBC=1×1.031×105(1050)×103W_{BC}=-1×1.031×10^5(10-50)×10^{-3}

WBC=4124JW_{BC}=4124J

Work done in process CA;

WCA=0W_{CA}=0

Therefore,the net work done is;

Wnet=QAB+QBC+QCAW_{net}=Q_{AB}+Q_{BC}+Q_{CA}

Wnet=8151.80+4124+0W_{net}=8151.80+4124+0

Wnet=12275.8JW_{net}=12275.8J


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