Question

The uniform bar weighs 45 N and is subjected to the forces as shown. Find the magnitude, location and direction of the force needed to keep the bar in equilibrium

Answer 1

$\Delta F_x=60+70+45-50-40=85~N,$

$\Delta F_y=69~N,$

$F=\sqrt{\Delta F_x^2+\Delta F_y^2}=110~N,$

$\alpha=\arctan\frac{\Delta F_y}{\Delta F_x}=39°.$