once kg of air expand at a constant temperature from a pressure of 820 kpa and a volume of 3 m³ to a pressure of 220 kpa. determine. a. change of Internal Energy b. change of Enthalpy
a)
ΔT=0, ⟹ U=0 J,\Delta T=0,\implies U=0~ J,ΔT=0,⟹U=0 J,
b)
H=U+p(V2−V1)=p(V2−V1)=1.8 MJ.H=U+p(V_2-V_1)=p(V_2-V_1)=1.8~MJ.H=U+p(V2−V1)=p(V2−V1)=1.8 MJ.
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