A blower handles 1kg/s of air at 20^(@)C and consumes a power of 15kW.The inlet and outlet velocities of air are 100m/s and 150m/s respectively.Find the exit air temperature assuming adiabatic conditions.Take c_(p) of air is 1.005kJ/kg-K.
Solution;
Given;
"\\dot{m}=1kg\/s"
"T_1=20^oc=293"
"W=15kW"
"V_1=100m\/s"
"V_2=150m\/s"
"c_p=1.00kJ\/kgK"
The process is adiabatic;
"Q=0"
Apply steady flow energy equation;
"\\dot{m}(h_1+\\frac{V_1^2}{2000})+W=\\dot{m}(h_2+\\frac{V_2^2}{2000})"
where;
"h=c_pT"
By direct substitution;
"1[(1.005 \\times 293)+\\frac{100^2}{2000}]+15=1[(1.005\\times T_2)+\\frac{150^2}{2000})"
"314.465=1.005T_2+11.25"
"T_2=301.7064K" or "28.71^oc"
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