Question

30g of metal at 90oC is placed at 20oC in a calorimeter of mass 70g made of the same metal. If the final temperature is 22.1oC. Calculate the specific heat capacity of the metal.

Answer 1

$Q_1=Q_2,$

$Q_1=cm_1(t_1-t),$

$Q_2=cm_2(t-t_2),$

$cm_1(t_1-t)=cm_2(t-t_2),$

$c=920~\frac J {kg\cdot °C}.$