Answer to Question #248495 in Molecular Physics | Thermodynamics for Rod

Question

Find the range of an arrow that leaves the box at 50 m/s at ang angle of 50o above the horizontal?

Answer 1

Solution;

Given;

Initial velocity,$v_i$=$50m/s$

Angle of projection,$\theta$ =50°

Calculate the range ,R ,as follows;

$R=\frac{v_i^2}{g}sin(2\theta)$

$R=\frac{50^2}{9.81}×sin(100)$

$R=250.97m$

Answer;

$R=251m$