We know that linear expansion
l1=l(1+αΔT)...(i)
Area expansion
A1=A(1+βΔT)=l2(1+βΔT)...(ii)
Volumetric expansion
V1=V(1+γΔT)...(iii)
But we know that area (A1)=llength×lbase=l2(1+αΔT)2
Now, taking the bi-nominal expansion,
A1=l2(1+2α)...(iv)
from equation (ii) and (iv)
So, β=2α
Similarly,
V1=A1×l1=l2(1+3α)...(v)
Hence, from equation (i) and (v)
So, γ=3α
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