Question #241610

A vector located in the second quadrant has an x-component of -80 m at an angle of 20°, as shown. Find the magnitude of the vector and its y-component.


1
Expert's answer
2021-09-25T15:55:23-0400

Fy=Fxcot⁡20°=220,F_y=F_x\cot20°=220,

F=Fx2+Fy2=234.F=\sqrt{F_x^2+F_y^2}=234.


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