Answer to Question #241455 in Molecular Physics | Thermodynamics for Kelani

Question

What average mechanical power (in W) must a 61.5 kg mountain climber generate to climb to the summit of a hill of height 345 m in 49.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the power that must be produced by the climber's body.

__W

Answer 1

The power is work over time:

$$P=\frac Wt=\frac{mgh}t=\frac{61.5·9.8·345}{49·60}=70.7\text{ W}.$$