Question #240859

A 29.0 cm long spring is hung vertically from a ceiling and stretches to 35.7 cm when a 7.00 kg mass is hung from its free end.


(a)

Find the spring constant (in N/m).

 __N/m


(b)

Find the length of the spring (in cm) if the 7.00 kg weight is replaced with a 165 N weight.

__ cm


1
Expert's answer
2021-09-25T03:55:26-0400

(a)

Δx=35.729.0=6.7  cm=0.067  mMg=kΔx7.0×9.8=k×0.067k=68.60.067=1023.88  N/mΔx = 35.7-29.0 = 6.7 \;cm = 0.067 \;m \\ Mg=kΔx \\ 7.0 \times 9.8 = k \times 0.067 \\ k = \frac{68.6}{0.067}=1023.88 \;N/m

(b)

Mg=165  N165=1023.88×ΔxΔx=1651023.88=0.1611  =16.11  cmMg = 165 \;N \\ 165 = 1023.88 \times Δx \\ Δx = \frac{165}{1023.88} = 0.1611 \; = 16.11 \;cm


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS