Answer to Question #308589 in Mechanics | Relativity for Anna

Question

An object oscillates with simple harmonic motion along the x-axis, its position varies with time. According to the equation. x(t) = 4 Cos(πt + π/3 ). The time is given in a sec and the angles are in radian. a) Draw a free hand wave diagram. b) Determine the amplitude, frequency, and time period of the motion. c) Calculate the velocity and acceleration of the object at any time ‘t’. d) Using the result of part ‘b’,find velocity and acceleration at t = 5 sec.

Answer 1

Solution.

$x(t)=4cos(\pi t+\dfrac{\pi}{3});$

$b) x(t)=Acos(wt+\phi _0);$

$A=4m; w=\pi rad;$

$w=2\pi f\implies f=\dfrac{w}{2\pi};$

$f=\dfrac{\pi}{2\pi}=\dfrac{1}{2} s^{-1};$

$T=\dfrac{1}{f};$ $T=\dfrac{1}{0.5}=2s;$

$c) v(t)=x^{'}(t)=-4\pi sin(\pi t+\dfrac{\pi}{3});$

$a(t)=v^{'}(t)=-4\pi^2cos(\pi t+\dfrac{\pi}{3});$

$d) v(5)=-4\sdot 3.14\sdot sin(5\pi+\dfrac{\pi}{3})=10.87 m/s;$

$a(5) =-4\sdot 3.14^2\sdot cos(5t+\dfrac{\pi}{3})=19.72 m/s^2;$

Answer: $b) f=0.5s^{-1}; T=2s;$

$c)v(t)=-4\pi sin(\pi t+\dfrac{\pi}{3});a(t)=-4\pi^2cos(\pi t+\dfrac{\pi}{3});$

$d)v(5)=10.87 m/s; a(5)=19.72 m/s^2.$