A uniform 10 kg ladder 2.5 m long is placed against a frictionless wall with its base on the ground 80 cm from the wall.
Find the magnitude of the force exerted on the wall and on the ground.
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Expert's answer
2022-03-10T10:18:32-0500
Explanations & Calculations
Since the wall is frictionless, the only force acting on the ladder by the wall is the normal reaction force say R.
And the floor should have friction to keep the ladder sliding on the floor so there are 2 forces acting on the ladder from the floor: the normal force and the friction force say S and f respectively.
With the horizontal equilibrium, it is obvious that f=R and from the vertical equilibrium S=mg therefore, only R or f needs to be found.
Take moment around the point where the ladder touches the floor.
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