Question #305385

A car is stopped at a traffic light. It then travels along a straight road such



that its distance from the light is given by:



š‘„(š‘”) = 2.4š‘”



2 āˆ’ 0.120š‘”



3

Expert's answer

x=2.4t2āˆ’0.120t+3x=2.4t^2-0.120t+3

Differentiate with respect to time

v=dxdtv=\frac{dx}{dt}

v=d(2.4t2āˆ’.120t+3)dt=4.8tāˆ’0.120v=\frac{d(2.4t^2-.120t+3)}{dt}=4.8t-0.120

v=0v=0

4.8tāˆ’0.120=04.8t-0.120=0

t=0.1204.8=0.025sect=\frac{0.120}{4.8}=0.025sec


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