calculate the density, specific weight and weight of 1.5 liters of gasoline with a specific gravity of 0.70
Answer
Sg=0.70
Volume
V=1.5∗10−3m3*10^{-3}m^3∗10−3m3
Let mass is m kg
So density
d=Sg.ρ=0.7∗1000=700kg/m3d=Sg.\rho=0.7*1000\\=700kg/m^3d=Sg.ρ=0.7∗1000=700kg/m3
Specific weight
=dg=700∗9.81=6867N/m3=dg\\=700*9.81\\=6867N/m^3=dg=700∗9.81=6867N/m3
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