Calculate the specific weight, specific mass, specific volume and specific gravity of a liquid having a volume of 5 cubic meters and its weight is 35 kilo newton
Answer
Weight of liquid
"W=35KN"
So it's mass becomes
"M=\\frac{W}{g}\\\\=\\frac{35000}{9.81}\\\\=3567.8Kg"
Volume
"V=5m^3"
So
"Specific \\space weight\n\\\\\\gamma=\\frac{W}{V}\\\\=\\frac{35000}{5}\\\\=7000N\/m^3"
Specific mass
M=3567.8Kg
Density
"\\rho =\\frac{M}{V}\\\\=\\frac{3567.8}{5}\\\\=711.54Kg\/m^3"
Specific volume
"v=\\frac{V}{M}\\\\=\\frac{5}{3567.8}\\\\=0.0014m^3\/kg"
Specific gravity
"Sg=\\frac{\\gamma}{\\gamma_{at 4\u00b0C}}\\\\=\\frac{7.000}{9.81}\\\\=0.71"
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