Explanation & Calculation
The relativistic mass is given by the following formula and upon substitution of the given values into it, you can get the answer. M r e l a t i v i s t i c = m r e s t 1 − v 2 c 2 \qquad\qquad
\begin{aligned}
\small M_{relativistic}&=\small \frac{m_{rest}}{\sqrt{1-\large\frac{v^2}{c^2}}}
\end{aligned} M re l a t i v i s t i c = 1 − c 2 v 2 m res t
v = 55 100 c ⟹ v 2 c 2 = 5 5 2 10 0 2 \qquad\qquad
\begin{aligned}
\small v&=\small \frac{55}{100}c\\
\implies \small \frac{v^2}{c^2}&=\small\frac{55^2}{100^2}
\end{aligned} v ⟹ c 2 v 2 = 100 55 c = 10 0 2 5 5 2
Then the required answer is M r = 9.1 × 1 0 − 31 k g 1 − 5 5 2 10 0 2 = 1.1 × 1 0 − 30 k g ⋯ ( increased ) \qquad\qquad
\begin{aligned}
\small M_r&=\small \frac{9.1\times10^{-31}\,kg}{\sqrt{1-\frac{55^2}{100^2}}}\\
&=\small 1.1\times10^{-30}\,kg\cdots(\text{increased})
\end{aligned} M r = 1 − 10 0 2 5 5 2 9.1 × 1 0 − 31 k g = 1.1 × 1 0 − 30 k g ⋯ ( increased )
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