Derive the equation a pentulam T.It depends on mass of the bob,length of the pentulam and acceleration due gravity?
Period T=T=T= time to complete one oscillation
At Equilibrium T0=mgT_0=mgT0=mg
Restoring force on the pendulum mass displaced Fe=−mgsinθF_e=-mgsin\thetaFe=−mgsinθ
For small displacements sinθ=θsin\theta=\thetasinθ=θ
θ=displacementxLengthl=xl\theta=\frac{displacement x}{Length l}=\frac{ x}{ l}θ=Lengthldisplacementx=lx
Thus:
Fe=−mg(xl)Fe=-mg(\frac{x}{ l})Fe=−mg(lx)
From Newton's second law a=Fem=−gxla=\frac{F_e}{m}=- \frac{g x}{ l}a=mFe=−lgx
Also for simple harmonic motion a=−xω2a=-x\omega^2a=−xω2
−xω2=−gxl-x\omega^2=-\frac{gx}{l}−xω2=−lgx
ω=g/l\omega=\sqrt{g/l}ω=g/l
Since period T=2π/ωT=2\pi/\omegaT=2π/ω
T=2πl/gT=2\pi\sqrt{l/g}T=2πl/g
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