Answer to Question #307456 in Field Theory for Anne

Question

 Find the magnitude of an electron's electric field if the field itself is 50cm away from it.

Answer 1

he electric field due the point charge

$$E=k\frac{q}{r^2}$$ $$E=9*10^9*\frac{1.6*10^{-19}}{0.5^2}=5.76*10^{-9}\:\rm V/m$$