Answer to Question #306802 in Field Theory for isay

Question

Find the magnitude of an electron's electric field if the field itself is 50cm away from it.

Answer 1

The electric field

$$E=k\frac{q}{r^2}\\ =9*10^9*\frac{1.6*10^{-19}}{0.5^2}=5.76*10^{-9}\:\rm V/m$$