Question

How far apart are two charges , one of magnitude is 3 uC and the other magnitude is 5uC if the force between them is 20N

Answer 1

Answer

Electrostatic force due two point charge is given by

$F=\frac{kqq'}{r^2}$

So distance

$r=\sqrt{\frac{kqq'}{F}}$

$r=\sqrt{\frac{9*10^9*3*10^{-6}5*10^{-6}}{20}}\\=8.22cm$