How far apart are two charges , one of magnitude is 3 uC and the other magnitude is 5uC if the force between them is 20N
Answer
Electrostatic force due two point charge is given by
"F=\\frac{kqq'}{r^2}"
So distance
"r=\\sqrt{\\frac{kqq'}{F}}"
"r=\\sqrt{\\frac{9*10^9*3*10^{-6}5*10^{-6}}{20}}\\\\=8.22cm"
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