Answer to Question #267292 in Field Theory for zzzz

Question #267292

Lucy and her bike together have a mass of 120 kg she slows down from 4.5m/s to 3.5 m/s how much kinetic energy does she lose


1
Expert's answer
2021-11-17T10:39:31-0500

We can find the losses in kinetic energy as follows:


KEloss=ΔKE=KEfKEi,KE_{loss}=\Delta KE=KE_f-KE_i,KEloss=12m(vf2vi2),KE_{loss}=\dfrac{1}{2}m(v_f^2-v_i^2),KEloss=12×120 kg×((3.5 ms)2(4.5 ms)2)=480 J.KE_{loss}=\dfrac{1}{2}\times120\ kg\times((3.5\ \dfrac{m}{s})^2-(4.5\ \dfrac{m}{s})^2)=-480\ J.

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