Question #253359

an object slide down an inclined plane from an initial height of 30m its velocity at the foot of the plane is 20ms, the percentage of its initial potential energy which is clssinated as heat is

Expert's answer

The initial potential energy of an object

Ep=mghE_p=mgh

The final kinetic energy of the object

Ek=mv22E_k=\frac{mv^2}{2}

The amount of mechanical energy transred into heat

Ep−EkEp100%=mgh−mv2/2mgh100%=(1−v2/2gh)100%=(1−202/(2∗9.8∗30))∗100%=32%\frac{E_p-E_k}{E_p}100\%=\frac{mgh-mv^2/2}{mgh}100\%\\ =(1-v^2/2gh)100\%\\=(1-20^2/(2*9.8*30))*100\%=32\%


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