Question #249058

an electron released from rest in uniform electric field of magnitude e=220 n/c and gains speed. find magnitude of force applied to it


Expert's answer

The field of magnitude EE acts on the point charge qq with force F=qEF = q E. Therefore, F=1.6⋅10−19C⋅220NC≈3.5⋅10−17NF = 1.6 \cdot 10^{-19} C\cdot 220 \frac{N}{C} \approx 3.5 \cdot 10^{-17} N.


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