Question

A ball is thrown vertically upward with a speed of +18 m/s. (assume g=10 m/s2

)

a. How high does it rise?

Answer 1

From third equation of motion ,$v^ 2 =u ^2−2gh$

$0=u ^2 −2g\frac{h}{2}$

$h = \frac{u^2}{g}$

= $\frac{18^2}{10}$

h= 32.4m

Therefore, ball rises to 32.4m