A ball is thrown vertically upward with a speed of +18 m/s. (assume g=10 m/s2
)
a. How high does it rise?
From third equation of motion ,v2=u2−2ghv^ 2 =u ^2−2ghv2=u2−2gh
0=u2−2gh20=u ^2 −2g\frac{h}{2}0=u2−2g2h
h=u2gh = \frac{u^2}{g}h=gu2
= 18210\frac{18^2}{10}10182
h= 32.4m
Therefore, ball rises to 32.4m
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