Answer to Question #226437 in Field Theory for EZOCH

Question

A ball of mass 0.1kg is thrown vertically upwards with an initial velocity of 80m/s. Calculate the potential energy halfway up

Answer 1

Let's calculate the maximum height

$H=\frac {v^2} {2g} =320m$

PE=mgh=0.1×10×320=320 J

at halfway up PE will be half of max = $\frac {320} {2} =160 J$

KE will be equal to PEmax=320 J