Three point charges 10 C, -20 C, and -50 C are at the three consecutive corners of a square 10 cm on a side. What is the potential energy of the system?
Potential energy
U1=kq1q2rU_1=\frac{kq_1q_2}{r}U1=rkq1q2
U1=k×10×(−20)0.12U_1=\frac{k\times10\times(-20)}{0.1^2}U1=0.12k×10×(−20)
U1=−1.8×1014JU_1=-{1.8\times10^{14}}JU1=−1.8×1014J
U2=kq2q3r2U_2=\frac{kq_2q_3}{r^2}U2=r2kq2q3
U2=k×20×500.12=9×1014JU_2=\frac{k\times20\times50}{0.1^2}=9\times10^{14}JU2=0.12k×20×50=9×1014J
U=U12+U22U=\sqrt{U_1^2+U_2^2}U=U12+U22
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment